Given that the coordinates of the point A is (2,7) and the coordinates of the point B is (6,3)
We need to determine the midpoint of A and B
<u>Midpoint of A and B:</u>
The midpoint of A and B can be determined using the formula,

Substituting the points (2,7) and (6,3) in the above formula, we get;

Adding the numerator, we have;

Dividing the terms, we get;

Thus, the midpoint of the points A and B is (4,5)
Answer:
Graph = Cardioid
Axis of symmetry = y-axis
Critical points= 
Step-by-step explanation:
General equation for this type of cardioid is:
a ± b sinθ
Condition for a cardioid = 
Axis of symmerty according to the graph of 2 + 2 sinθ is along y-axis.
Critical points:
r = 2 + 2 sinθ ⇒ r = 2(1 + sinθ) ⇒ r' = 2 cosθ
∵derivative of 1 + sinθ = cosθ
For finding critical point the derivative is equal to zero,
2 cosθ = 0 ⇒ cosθ = 0
the value of cosθ is equal to zero at intervals: 
So, critical points = 
28 number of Houses = 40%
of the total houses the cleaning company needs to clean in a week.
Find the total number of houses do the cleaning company needs to clean in
a week>
=> 28 number of houses / 40%
=> 28 / 0.4
=> 70
Thus, the total number of houses that a cleaning company needs to clean in
the whole week is 70 houses.
Since they already cleaned 40% of it, which is 28, thus, they still need
to clean 42 more.
Answer:
Incomplete question
Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.
a. Determine the pre-collision momentum of the ball.
b. Determine the post-collision momentum of the ball.
c. Determine the momentum change of the ball.
Answer:
A. 1.5353kgm/s
B. 1.6963kgm/s
C. 0.161kgm/s
Step-by-step explanation:
A. The pre-collision momentum of the ball = mass of ball × velocity of ball
Mass of ball = 57.5g = 0.0575kg
Velocity of ball = 26.7m/s
Pre-collision momentum of ball = 0.0575×26.7
= 1.5353kgm/s
B. Post collision momentum of the ball = mass of ball × velocity of ball after impact
Velocity of ball after impact = 29.5m/s
Post collision momentum of ball after impact = 0.0575×29.5
= 1.6963kgm/s
C. Momentum change of ball = momentum after impact - momentum before imlact
= 1.6963kgm/s - 1.5353kgm/s
= 0.161kgm/s