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3 years ago

Given the formula, Sn=a 1-r^n/1-r, what is the sum of the first nine terms of the geometric series: 324, -108, 36, -12...

Mathematics

1 answer:

vlada-n [284]3 years ago

3 0

Answer:

243.01.

Step-by-step explanation:

The first term (a) = 324.

The common ratio (r) = -108/324 = -1/3.

So sum of 9 terms is:

S(9) = 324 * (1 - (-1/3)^9) / ( 1 - (-1/3)

= 324 ( 1 - (-0.00005076)) / 4/3

= 324 * 1.00005076 / 1.33333

= 243.012.

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lutik1710 [3]

Answer:

Step-by-step explanation:

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2 years ago

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Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be 27

german

Answer:

n = 78

Step-by-step explanation:

IQR is the interquartile range of the data set.

So Saul had already arranged the data in order, that is the first step when calculating the interquartile range.

25, 30, 50, 50, 50, 50, 56, n., 250

Next, is to find the median so we could easily separate the data into quartiles.

The median of the data 25, 30, 50, 50, 50, 50, 56, n., 250 = 50

Then, arrange the data into the first quartile and the third quartile

first quartile = 25, 30, 50, 50

third quartile = 50, 56, n., 250

first quartile median = 30 + 50 = 80/2 = 40

third quartile = 56 + n /2

The interquartile range formula is the first quartile subtracted from the third quartile:

IQR = Q3 – Q1.

Since 27 is the interquartile range, n=

27 = (56 + n /2) - 40

Use 2 to multiply through to eliminate the denominator

54 = (56 + n) - 80

n = 78

5 0

3 years ago

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them

Mariulka [41]

Answer:

Two possible answers below

Step-by-step explanation:

Probability and Sets

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

$\displaystyle P=\frac{19}{29}$

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

$\displaystyle P=\frac{17}{29}$