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svlad2 [7]
3 years ago
13

....Math I need help

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0
M<FIB = 90 -  (4x+3)
m<FIB = 87 - 4x

---------------------
m<HFG = 90 - (5x + 4)
m<HFG = 86 - 5x

-------------------------------
<BCF = 180 - (<CBF + <CFB)
<CBF  = 10x + 3
<CFB =90 - <CFD
but <CFD = <HFG = 86 - 5x (vertical angles)

<CFB =90 -(86 - 5x) = 4 + 5x

<BCF = 180 - (10x + 3  + 4 + 5x)
<BCF = 180 - (15x + 7)
<BCF = = 173 - 15x

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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
Find y when x=14 if y varies inversely as x and y=5 when x=8
DanielleElmas [232]
Y = k/x
5 = k/8
k = 5 x 8 = 40
Therefore,
y = 40/14 = 2.86
8 0
3 years ago
The profitability, P, of a popular restaurant franchise can be modeled by the function P (t) = t4 – 10t3 + 28t2 – 24t, where t i
vekshin1

In this question, the profit of the restaurant after t months is given by a polynomial function. To find when it begins to show a profit, we find the numerical values of the function for t, and it shows a profit when t > 0

Profit after t months:

P(t) = t^4 - 10t^3 + 28t^2 - 24t

0 months:

This is P(0). So

P(0) = 0^4 - 10*0^3 + 28*0^2 - 24*0 = 0

1 month:

This is P(1). So

P(1) = 1^4 - 10*1^3 + 28*1^2 - 24*1 = -5

2 months:

This is P(2). So

P(2) = 2^4 - 10*2^3 + 28*2^2 - 24*2 = 0

3 months:

This is P(3). So

P(3) = 3^4 - 10*3^3 + 28*3^2 - 24*3 = -9

4 months:

This is P(4). So

P(4) = 4^4 - 10*4^3 + 28*4^2 - 24*4 = -32

5 months:

This is P(5). So

P(5) = 5^4 - 10*5^3 + 28*5^2 - 24*5 = -45

6 months:

This is P(6). So

P(6) = 6^4 - 10*6^3 + 28*6^2 - 24*6 = 0

7 months:

This is `P(7). So

P(7) = 7^4 - 10*7^3 + 28*7^2 - 24*7 = 175

After 7 months it shows profit, so it starts showing profit on the 6th month, and thus, the correct answer is given by option D.

For another example of a function involving numeric value, you can check brainly.com/question/24231879

8 0
3 years ago
I buy a MP3 player for £40 in a sale where it was 20% off. What was the original price
natta225 [31]
20% off means you paid only 80% of the original price.
0.8x=40
x=40÷0.8=50
so the original price is 50
6 0
3 years ago
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This is urgent 1. In a picture, there are 40 monkeys, and 60% of the monkeys are in the trees.
V125BC [204]

Answer:

There are 60 monkeys in the Zoo

Step-by-step explanation:

3 0
2 years ago
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