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svlad2 [7]
3 years ago
13

....Math I need help

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
3 0
M<FIB = 90 -  (4x+3)
m<FIB = 87 - 4x

---------------------
m<HFG = 90 - (5x + 4)
m<HFG = 86 - 5x

-------------------------------
<BCF = 180 - (<CBF + <CFB)
<CBF  = 10x + 3
<CFB =90 - <CFD
but <CFD = <HFG = 86 - 5x (vertical angles)

<CFB =90 -(86 - 5x) = 4 + 5x

<BCF = 180 - (10x + 3  + 4 + 5x)
<BCF = 180 - (15x + 7)
<BCF = = 173 - 15x

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the length of the rectangle is 2 less than 3 times the width. The perimeter is 12. Find the length and the width.
In-s [12.5K]

width=2
length= 4

explanation in the attached picture
5 0
2 years ago
What is EG? Round to the nearest tenth if necessary.
slava [35]

Answer:

26.

Step-by-step explanation:

As the vertex angles are equal:

24/54 = x / x+10

54x = 24x + 240

30x = 240

x = 8

So EG = x + x + 10

=  8 + 8 + 10

= 26..

7 0
3 years ago
Simplify using appropriate property: 5/7 X 1/5 + 5/7 X 3/5Simplify using appropriate property:
chubhunter [2.5K]

Answer:

4/7

Step-by-step explanation:

5/7 x (1/5+3/5) = 5/7 x 4/5 = 4/7

8 0
3 years ago
Among two supplementary angles, the measure of the larger angle is 44°
zhuklara [117]

Answer:

68° and 112°

Step-by-step explanation:

Supplementary angles sum to 180°

let the smaller angle be x then the larger angle is x + 44 , then

x + x + 44 = 180 , that is

2x + 44 = 180 ( subtract 44 from both sides )

2x = 136 ( divide both sides by 2 )

x = 68

Smaller angle = 68° and

larger angle = x + 44 = 68 + 44 = 112°

6 0
3 years ago
Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0
3 years ago
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