B) is an arithmetic sequence because you are adding by 2 each time. The other sequences don’t match this criteria.
I’m sorry I’m not sure what else to say I hope this somewhat helped :/
Have a great day :)
Answer:
x = 15.75
Step-by-step explanation:
I'm going to assume you mean solve for x so:

Answer:
a) 0.857
b) 0.571
c) 1
Step-by-step explanation:
Based on the data given, we have
- 18 juniors
- 10 seniors
- 6 female seniors
- 10-6 = 4 male seniors
- 12 junior males
- 18-12 = 6 junior female
- 6+6 = 12 female
- 4+12 = 16 male
- A total of 28 students
The probability of each union of events is obtained by summing the probabilities of the separated events and substracting the intersection. I will abbreviate female by F, junior by J, male by M, senior by S. We have
- P(J U F) = P(J) + P(F) - P(JF) = 18/28+12/28-6/28 = 24/28 = 0.857
- P(S U F) = P(S) + P(F) - P(SF) = 10/28 + 12/28 - 6/28 = 16/28 = 0.571
- P(J U S) = P(J) + P(S) - P(JS) = 18/28 + 10/28 - 0 = 1
Note that a student cant be Junior and Senior at the same time, so the probability of the combined event is 0. The probability of the union is 1 because every student is either Junior or Senior.
Answer:
<h2>
26</h2>
Step-by-step explanation:

Answer:
<em>J ) j = - 3,</em>
<em>K ) h = 9,</em>
<em>M ) d = - 24,</em>
<em>N ) x = 1 / 2</em>
Step-by-step explanation:
J )

I applied the distributive property, resulting in the second step. Afterwards I subtracted 4 from either side of the equation, received - 22j = 66 after combining like terms, and divided - 22 on either side to get j = -3.
K )

Multiplying each end of the equation by 3 resulted in the simplified expression 4h = 36. Dividing either side by 4, I got h = 9.
M )

Taking the LCM of 4 and 3, I got 12, multiplying either side by 12 / 12. Combining like terms and dividing - 1 on either side of the equation - d = 24, I received d = - 24.
N )

After dividing the first equation by - 2 on each end, I received a simplified equation that, by adding 3 on it's part, got x to be = 1 / 2