1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mel-nik [20]
3 years ago
15

£440 is divided between David, Mark & Henry so that David gets twice as much as Mark, and Mark gets three times as much as H

enry. How much does Mark get?
Mathematics
1 answer:
Lesechka [4]3 years ago
8 0

Mark received £ 132

<em><u>Solution:</u></em>

Given that £440 is divided between David, Mark & Henry

Let "d" be the share of david

Let "m" be the share of mark

Let "h" be the share of henry

Total amount is 440

Therefore,

share of david + share of mark + share of henry = 440

d + m + h = 440 ------- eqn 1

<em><u>David gets twice as much as Mark</u></em>

d = 2m ----- eqn 2

<em><u>Mark gets three times as much as Henry</u></em>

m = 3h

h = \frac{m}{3}  ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

2m + m + \frac{m}{3} = 440\\\\\frac{6m + 3m + m}{3} = 440\\\\10m = 1320\\\\m = 132

Thus Mark received £ 132

You might be interested in
A plane flew 2,190 kilometers from Chicago to Flagstaff. Another plane flew 2,910 kilometers from Chicago to Oakland. How much f
DiKsa [7]
The answer is 720.hope it helps.
3 0
3 years ago
Read 2 more answers
Suppose that only 65% of all drivers in a certain state wear a seat belt. a random sample of 80 drivers is selected. what is the
jonny [76]

Answer:

Pr(X >42) = Pr( Z > -2.344)

                = Pr( Z< 2.344) = 0.9905

Step-by-step explanation:

The scenario presented can be modeled by a binomial model;

The probability of success is, p = 0.65

There are n = 80 independent trials

Let X denote the number of drivers that wear a seat belt, then we are to find the probability that X is greater than 42;

Pr(X > 42)

In this case we can use the normal approximation to the binomial model;

mu = n*p = 80(0.65) = 52

sigma^2 = n*p*(1-p) = 18.2

Pr(X >42) = Pr( Z > -2.344)

                = Pr( Z< 2.344) = 0.9905

7 0
3 years ago
Given f(x)=x-10. what is f(-7)
Vlad [161]
f( - 7) = ( - 7) - 10 \\ = -1 7
answer is -17
5 0
2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Can someone can help me plsssssss
Darina [25.2K]
The answer is letter A
8 0
3 years ago
Read 2 more answers
Other questions:
  • How many regular triangles meet at a vertex to form a regular tessellation?
    6·2 answers
  • A candy maker had a piece of taffy that was 53 inches long. If he chopped it into 6 equal length pieces, how long would each pie
    10·2 answers
  • Avril types essays for students from her home. On average, she can type a page in about 10 2/3 minutes. she spends 54 1/2 minute
    14·1 answer
  • A number times the sum of 5 and 8 is 42
    11·2 answers
  • You worked the following hours this week: Monday 8 AM to 5 PM, Tuesday 9 AM to 3 PM, Thursday 8:30 AM to 2:15 PM. You get a 30-m
    7·2 answers
  • I have 3 lemonades I drink 1, I give 1 to my sister and the third one, I leave it. How many do I have? (Easy)
    6·1 answer
  • Find the value of h(-7) for the function below:
    11·1 answer
  • Hi i have a question can younplease help me ​
    12·1 answer
  • Need help ace plsssz​
    8·1 answer
  • Please solve this for me
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!