Answer:
sqrt(2^4) sqrt(5)
Step-by-step explanation:
sqrt(80)
sqrt(80) = sqrt(16*5)
We know that sqrt(ab) =sqrt(a) sqrt(b)
sqrt(16) sqrt(5)
sqrt(4*4) sqrt(5)
sqrt(2*2*2*2) sqrt(5)
sqrt(2^4) sqrt(5)
Answer: 10.5cm
Step-by-step explanation: the radius is half the diameter. 21/2=10.5
3 + 3/4x > = 15
3/4x > = 15 - 3
3/4x > = 12
x > = 12 / (3/4)
x > = 12 * 4/3
x > = 48/3 = 16 sessions <==
================
-p - 4p > -10
-5p > -10
p < -10/-5
p < 2 <===
===============
-3 - 6(4x + 6) > = 9
-3 - 24x - 36 > = 9
-24x - 39 > = 9
-24x > = 9 + 39
-24x > = 48
x < = -48/24
x < = -2 <===
=================
2x - 2 > = 10
2x > = 10 + 2
2x > = 12
x > = 12/2
x > = 6........so ur solution set is {6,7}
Right triangle can be rotated to create a cone!
Answer:
82.31% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Approximately what percentage of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter?
This is the pvalue of Z when X = 5.4 subtracted by the pvalue of Z when X = 4.2. So
X = 5.4



has a pvalue of 0.9842
X = 4.2



has a pvalue of 0.1611
0.9842 - 0.1611 = 0.8231
82.31% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per microliter