Question

What is the 45th team of the arithmetic sequence 58,61,64,67

Answer 1

Answer:

The 45th term is 190.

Step-by-step explanation:

The easiest way to approach this problem is to find an equation for the nth term of the sequence.  Here the first term is 58 and the common difference is 3; that is, each term is equal to the previous term, plus 3.  The appropriate equation is thus:

a(n) = a(1) + 3(n-1).  Check.  What is a(2)?  Find 58 + 3(1).  It's 61, and correct.

Therefore, the 45th term is:

a(45) = 58 + 3(45-1) = 58 + 3(44) = 190