The standard form of the quadratic function in this problem is given as follows:
y = -0.25(x² - 4).
<h3>How to define the quadratic function?</h3>
The standard definition of a quadratic function is given as follows:
y = ax² + bx + c.
Considering it's roots x' and x'', the definition are given as follows:
y = a(x - x')(x - x'')
In which a is the leading coefficient.
From the table given by the image at the end of the answer, the roots are given as follows:
x' = -2, x'' = 2.
(as they are the values of x for which y = 0).
Then:
y = a(x + 2)(x - 2)
y = a(x² - 4).
When x = 0, y = 1, hence the leading coefficient is given as follows:
1 = -4a
a = -1/4.
a = -0.25.
Hence the equation is of:
y = -0.25(x² - 4).
<h3>Missing Information</h3>
The table is given by the image shown at the end of the answer.
More can be learned about quadratic functions at brainly.com/question/24737967
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Step-by-step explanation:
- Subtract 1 from both sides to get x alone. So, you have f(x) - 1 = x^2.
- Now, square root both sides to remove the squared from x. So, you have...
- I hope this helps!
Answer:
Step-by-step explanation:-1/3(6x+18)+3x+5= -2x - 6 + 3x + 5 = x - 1. QED
Answer:
x
Step-by-step explanation: