Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
C,D and F are correct.
C is what you would think of when reading it, you walked 12 and walked 1/4(12) more.
12 + 12(1/4) =
12 + 3 =
15
D is equal to C when simplified,
12(1+1/4) =
12 + 3 =
15
F is the same as the D, it just simplified the numbers in the parenthesis
12(1+1/4) =
12(4/4 + 1/4) =
12(5/4) =
15
Answer:
0
Step-by-step explanation:
Theres different ways you can solve this but the way I did it both sides were equal to eachother.
If your looking for greatest common factors they are 1,67, c,and d.