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4 years ago

A rectangular swimming Pool measures 50 meters in length and 25 in widths. What are the length and width of the scale drawing

Mathematics

2 answers:

Westkost [7]4 years ago

5 0

Answer: The length is 5 and the width is 1.

50 ÷ 5= 10

25 ÷ 5 = 5

* Hopefully this helps:) Mark me the brainliest:)!!

user100 [1]4 years ago

4 0

Answer:

What is the scale

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Sophie [7]

Answer:

=9.8 . -- : .

6 0

3 years ago

What is the answer for this

Brilliant_brown [7]

Parallelogram

Area: 24m²

Perimeter: 26m

Trapezoid

Area:21cm²

Perimeter:22.6cm

5 0

4 years ago

the train to hogwarts is moving at a speed of 120 mph. if hogwarts is 420 miles away, how long will the students train ride be ?

dexar [7]

Answer:

The train ride is 3.5 hours

Step-by-step explanation:

We know that distance is equal to rate times time

d = rt

We know the distance and the rate

420 = 120*t

Divide each side by 120

420/120 = 120t/120

3.5 =t

The train ride is 3.5 hours

4 0

3 years ago

Read 2 more answers

Which of the following equations has the same solutions as the equations 3x+2y=-12

Marianna [84]

B, C, E, F

<h2>Explanation:</h2>

In this problem, we have the following equation of a line written in Standard form:

$3x+2y=-12$

So we need to choose the equations that has the same solutions as this equation. If we multiply each equation by a constant term and find the same solution as the given equation, then they will have the same solution. This is only true fro options B, C, E and F.

Option B.

$-3x-2y= 12 \\ \\ Multiply \ both \ sides \ by \ -1: \\ \\ (-1)(-3x-2y)=(-1)(12) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option D.

$15x+10y= -60 \\ \\ Multiply \ both \ sides \ by \ 1/5: \\ \\ (\frac{1}{5})(15x+10y)=(\frac{1}{5})(-60) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option E.

$6x+2y= -12 \\ \\ Multiply \ both \ sides \ by \ 1/2: \\ \\ (\frac{1}{2})(6x+2y)=(\frac{1}{2})(-24) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

Option F.

$1.5x+y= -6 \\ \\ Multiply \ both \ sides \ by \ 2: \\ \\ (2)(1.5x+y)=(2)(-6) \\ \\ 3x+2y=-12$

So we get the same given equation. This option is valid!

For the other options, there is no any constant term that multiplies both sides of the equation and gives us the same given equation.

<h2>Learn more:</h2>

About this subject: brainly.com/question/8810210

#LearnWithBrainly

7 0

3 years ago

Solve for the equation for the interval [0, 2pi). sec x/2 = cos x/2

Alenkinab [10]

Sec(x/2) = 1/cos(x/2)

sec(x/2)=cos(x/2) ----> cos^2(x/2)=1 ---> cos(x/2) = -1 and cos(x/2) = 1

Cos(x/2)=1 --- > x/2 = 0, only. x = 0;

cos(x/2)=-1 ----> x/2 = pi -> x = 2pi. But the statement says [0,2pi), so 2pi can not be chosen.

Only x = 0.

In fact, your equation is equivalent to sec(x)=cos(x), for x in [ 0, pi), so yes, only x = 0 .

3 0

3 years ago