Mantago want to borrow 10,000 to buy a car. He examined his budget and decides that he can afford a payment of $200 a month

A consumer believes that a certain potato chip maker is putting fewer chips in their regular bags of chips than the advertised a

dybincka [34]

Answer:

a) No

b) No

c) P value is more than 0.05.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 12 ounces

Sample size, n = 49

P-value = 0.136

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 12\text{ ounces}\\H_A: \mu < 12\text{ ounces}$

We use One-tailed z test to perform this hypothesis.

a) Alpha, α = 0.05

Since, p-value > α,

The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.

b) Alpha, α = 0.10

Since, p-value > α,

The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.

c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.

3 0

3 years ago

Suppose that scores on a knowledge test are normally distributed with a mean of 60 and a standard deviation of 4.3. Scores on an

Sphinxa [80]

Question:

(c) Boris also took a logic test. His z-score on that test was +0.93 . Does this change the answer to which test Boris performed better on? Explain your answer using z-scores.

Answer:

The answers to the questions are;

(a) Based on the z score, Boris perform better on his aptitude test.

(b) Based on the z score, Callie perform better on his knowledge test .

(c) For Boris since +0.93 = $z_{logic}$ > $z_{knowledge}$ > $z_{aptitude}$

Yes as Boris now performed best on the logic test.

Step-by-step explanation:

The z-score of a score is a measurement of the score withe respect to its distance from the mean as a factor of the standard deviation.

To solve the question, we note that we are required to find the z score as follows.

z score is given by $z = \frac{x -\mu}{\sigma}$

Where:

z = Standard score

x = Score

σ = Standard deviation

μ = Mean

(a) To find out which test did Boris performed better usin z score, we have

Boris scored a

57 on the knowledge test and

106 on the aptitude test

Therefore the z sore for the knowledge test is

$z = \frac{x -\mu}{\sigma}$

Here

x = 57

μ = 60

σ = 4.3

Therefore

$z_{knowledge} = \frac{57 -60}{4.3}$ = -3/4.3 = -30/43 = -0.6977

The z sore for Boris on the aptitude test is

Here

x = 106

μ = 110

σ = 7.1

$z_{aptitude} = \frac{106 -110}{7.1}$ = -40/17 = -0.5634

Based on the z score, Boris perform better on the aptitude test as his z score is higher (on the number line), --0.5634, compared to the z score on the knowledge test , -0.6977

(b) For Callie we have

Callie scored a

63 on the knowledge test and

114 on the aptitude test

Therefore the z sore for the knowledge test is

$z = \frac{x -\mu}{\sigma}$

Here

x = 63

μ = 60

σ = 4.3

Therefore

$z_{knowledge} = \frac{63 -60}{4.3}$ = 3/4.3 = 30/43 = 0.6977

The z sore for Callie on the aptitude test is

Here

x = 114

μ = 110

σ = 7.1

$z_{aptitude} = \frac{114 -110}{7.1}$ = 40/17 = 0.5634

Based on the z score, Callie perform better on the knowledge test as his z score is higher (on the number line), 0.6977, compared to the z score on the aptitude test , 0.5634.

(c) If $z_{logic}$ = +0.93 then sinc for Boris $z_{knowledge}$ = -0.6977 and

$z_{aptitude}$ = - 0.5634 then

$z_{logic}$ > $z_{knowledge}$ > $z_{aptitude}$

Therefore Boris now performed best on the logic test.

6 0

2 years ago

21 lbs of bananas cost $252. <br> How many lbs of bananas can you get with $420 ?

zhuklara [117]

Answer:

you would get 33.6 lbs of bananas

Step-by-step explanation:

420 ÷ 252 = 1.6 repeating