1/3x - 8 = y <== ur equation
Answer:
all real numbers greater than or equal to -1
Step-by-step explanation:
In order to solve this problem we need to know the vertex and the direction its pointing.
First we expand,
x^2-6x+8
To find the x value of the vertex we use this formula (-b/2a).
-(-6)/2(1) = 3
Now we plug 3 in the equation to get the y value,
(3)^2 - 6(3) + 8 = 9 - 18 + 8 = -1
The vertex is (3,-1)
We know the graph points up because x^2 is positive
The vertex is the lowest point, so we now know that -1 is the starting range and if the graph is pointing up, that means all values greater than -1.
This leads to our answer all real numbers greater than or equal to -1.
Answer:
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
Step-by-step explanation:
The following equations are given
a. 2 × 2× 2
b. 3 × 3 × 3 × 3
c. 4 × 4 × 4 × 5 × 5
d. 9 × 7 × 9 × 9 × 7 × 9
We need to find the index notation for the above equations
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
In this way it should be done
The same would be relevant
y/x = k
6.4/4 = 1.6
11.2 / 7 =1.6
16/10 = 1.6
20.8 /13 =1.6
This is a direct variation and the constant is 1.6
y=1.6x
