The rule of thumb for this kind of problem is that you must first determine the limiting variable in your situation. We know that for a single sandwich, 50 grams bread greatly exceeds the 9 grams of ham requirement. We also know that there will be a greater supply of ham since 1 kg is relatively close in amount to 1.2 kg. This means that we only need to look at the bread for calculation purposes. We can get the total number of sandwiches to be 1200 / 50 = 24 sandwiches.
The greatest common factor is found by finding the product of common primes.
91=7*13, 104=2*2*2*13 so the gcf of 91 and 104 is 13. Since the highest power of x and y in both terms is 1, the hcf for the variables is just xy
13xy
The Length would be 3
5+5= 10
16-10 =6 / 2 =3
Answer:
The distance is 8 cm
Step-by-step explanation:
The chord and the diameter form one leg and the hypotenuse of a right triangle. The other leg, BD, has length ...
BD² +AB² = AD²
BD² = AD² -AB² = 34² -30² = 256
BD = √256 = 16
The segment from the center of the circle to the midpoint of the chord is the midline of triangle ABD, so is half the length of BD.
distance from AB to the center = 16/2 = 8 . . . cm
To solve this, all you need to do is compare the ratio to the amount of SUVS there are.
5/9 (SUVs to sedans)
140/? (SUVs to sedans)
140 ÷ 5 = 28
9 x 28 = 252
140/252
There are 252 sedans in the car dealership! :D
