Question

The volume of a solid right pyramid with a square base is v units3 and the length of the base edge is y units. which expression represents the height of the pyramid? units (3v – y2) units (v – 3y2) units units

Answer 1

3v/y² units

Further explanation

Given:

• The volume of a solid right pyramid with a square base is v units³
• The length of the base edge is y units.

Question:

Which an expression represents the height of the pyramid?

The Process:

We will solve the problem of a geometric solid.

Let us recall the formula of volume of a right pyramid:

$\boxed{ \ V = \frac{1}{3} \times base \ area \times height \ }$

Because the base is square, we use the formula for square area, i.e., side times side.

Let us find out the height of the pyramid.

$\boxed{ \ Height = \frac{3v}{y \times y} \ }$

Thus, an expression represents the height of the pyramid is $\boxed{\boxed{ \ \frac{3v}{y^2} \ }}$ units

Learn more

1. What is the volume of each prism?  brainly.com/question/414021
2. The volume of rectangular prism  brainly.com/question/11613210
3. Express the volume of the box as a function of the length of the edge of the base. What is its domain? brainly.com/question/4925904

Keywords: the volume of a solid right pyramid, a square, the length of the base edge, an expression, represent, the height, the formula, a geometric solid, units

Answer 2

we know that

The volume of a solid right pyramid with a square base is equal to

$V=\frac{1}{3}*[ area\ of\ the\ base]*height$

area of the base is the area of a square

$area\ of\ the\ base=y^{2}\ units^{2}\\V=v\ units^{3}$

Substitute the values in the formula of volume

$v=\frac{1}{3}*[ y^{2}]*height$

solve for the height

$v=\frac{1}{3}*[ y^{2}]*height\\ \\height=\frac{3v}{y^{2}}\ units$

therefore

the answer is

$height=\frac{3v}{y^{2}}\ units$