3 years ago

Find an equation of variation in which y varies inversely as x and y = 5 and x = 17. then find the value of y when x=10

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

5 0

Y=5 -- x =17
so y= 5*10/17= 50/17 when x = 10

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Lines m and n are parallel and m<1=140*<br> What is m<7?

Arada [10]

$m\angle 7=180-m\angle 5\\
m\angle 5=m\angle 1=140\\
m\angle 7=180-140\\
m\angle 7=40$

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Susie is having a party with 15 guests. she wants to feed everyong sandwhiches.if susie buys 7 1/2 pounds of meat, how much meat

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-6(1 + 2v) – 7(v + 1) = -13

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Solve: x2 − x − 6/x2 = x − 6/2x + 2x + 12/x After multiplying each side of the equation by the LCD and simplifying, the resultin

Vesna [10]

The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

$\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}$

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

$\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}$

$\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}$

$\implies \frac{x^{2}-x-6 }{x^{2} } = \frac{5x +18}{2x}$

Multiply both the sides by x.

$\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}$

Again multiply both the sides by x

$2x^{2} -2x-12 = 5x^{2} +18x$

$\implies 5x^{2} -2x^{2} +18x +2x +12 = 0$

$\implies 3x^{2} + 18x+2x + 12 = 0$

Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

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brainly.com/question/2976807

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7 0

1 year ago

What is the solution to m + 15 = -29

AveGali [126]

Answer:

m = -44

Step-by-step explanation:

m + 15 = -29

-15 -15

m = -44

8 0

3 years ago

Read 2 more answers