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bonufazy [111]
3 years ago
9

Can anybody answer this equation??

Mathematics
2 answers:
kodGreya [7K]3 years ago
8 0
Answer: C. 18.6
9.3 x 2= 18.6
serious [3.7K]3 years ago
7 0

Answer:

18.6 (C)

Step-by-step explanation:

(I am assuming) it is a parallelogram, meaning that  R to the center = 1/2 (QR).

9.3 *2=QR, meaning that 18.6 is the answer.

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Simplify the expression:<br> 2(3n+4)-2(2n+5)
inessss [21]
First use distributive property:
2(3n + 4) - 2(2n + 5)
6n + 8 - 4n - 10
Group like terms:
6n - 4n + 8 - 10
Add like terms:
2n - 2
4 0
3 years ago
Read 2 more answers
Combine like terms : 2x+5x+10x
8090 [49]

Answer: =17x

Step-by-step explanation: hope this help, hope you understand it too.

Let's simplify step-by-step.

2x+5x+10x

Combine Like Terms:

=2x+5x+10x

=(2x+5x+10x)

=17x

7 0
3 years ago
14 + w is the same as which expression?
Vanyuwa [196]

Answer:

w+14,

Step-by-step explanation:

6 0
2 years ago
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
3 years ago
1 Point<br> The circle below is centered at (-3, 2) and has a radius of 3. What is its<br> equation?
arlik [135]

Answer:

(x + 3)^2 + (y - 2)^2 = 9

Step-by-step explanation:

<u>Equation for a circle:  (x – h)^2 + (y – k)^2 = r^2</u>

<u />

<u>Step 1:  Determine what h, k, and r are</u>

<em>h is the x value of the point:  -3</em>

<em>k is the y value of the point:  2</em>

<em>r is the radius of the circle:  3</em>

<u>Step 2:  Plug in and solve</u>

(x – h)^2 + (y – k)^2 = r^2

(x – (-3))^2 + (y – (2))^2 = (3)^2

<em>(x + 3)^2 + (y - 2)^2 = 9</em>

<em />

Answer:  (x + 3)^2 + (y - 2)^2 = 9

8 0
3 years ago
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