X in 5xy = 10 to solve the system
below.
x = 25 - y
5x + y =10
2 answers:
Answer:
5x+ y = 10 ---(eq1)
x = 25 - y ---(eq2)
substituting (eq2) in (eq1)
5(25 - y) + y = 10
125 - 5y + y = 10
125 - 4y = 10
-4y = 10 - 125
-4y = -115
4y = 115
y = 115/4 = 28.75
substituting value of y in (eq2)
x = 25 - 28.75
x = -3.75
Answer:
Step-by-step explanation:
there are two ways to solve systems of equations, elimination or substitution, this looks like elimination would work quickly
x= 25 -y
x + y = 25 (eq 1)
5x + y = 10 (eq 2)
subtract 2 from 1
x + y = 25
-(5x + y = 10)
-4x + 0y = 15
-4x = 15
x = - 15/4
now plug in x into either starting equations and solve for y
-15/4 + y = 25
y = 25 + 15/4
y = 100/4 + 15 /4
y = 115 /4
y = 28 3/4
we have solved it :)
You might be interested in
A
defenity i have a strong feeling
Answer:
3 trumpet players
Step-by-step explanation:
t=1 and 3x1=3t
Answer:
#8 is one #9 is 4
Step-by-step explanation:
Work shown above! X = 2 and y = 25
Answer:
Step-by-step explanation:
b in (-oo:+oo)
5*b+6 = -24 // + 24
5*b+6+24 = 0
5*b+30 = 0 // - 30
5*b = -30 // : 5
b = -30/5
b = -6
b = -6