Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Answer:

Step-by-step explanation:
Given


-- folded twice
Required
The area of the new rectangle
When the length was folder, the new length is:

When the width was folder, the new width is:

So, the new area is:



1,000,000/70=approx 142857 mins
142857/60=approx 2381 hours
2381/24=approx 99 days
If you want the answer more precisely then do the same calculations but use the exact value each time
Answer:
The other sides of triangles are 8.72 in and 8.72 in
Step-by-step explanation:
In a triangle ABC. Please find the attachment for figure.


Side BC=a = 10 in
Using sine law of trigonometry,

Substitute the given value into formula.


Cross multiply and we get

in
It is a isosceles triangle. Therefore, b=c=8.72 in
Hence, The other sides of triangles are 8.72 in and 8.72 in
Answer:
it would be 20
Step-by-step explanation:
because you divide to find the unit rate like 97.50/15 and then you multiply a number to the answer you got there until those two numbers have a product of 130