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Andru [333]
2 years ago
6

All of the following describes a balance sheet except which one

Mathematics
1 answer:
nikitadnepr [17]2 years ago
5 0
What is the question here???

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What is the unit rate of 20 and four?
ch4aika [34]
20
---- = 5
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Solve equation 3x-5y=7 5x-2y=-1 by elimination
kakasveta [241]

Answer:

x = -1, y = -2.

Step-by-step explanation:

Using the elimination method,

multiply the first eqn by 2 and the 2nd eqn by 5.

6x - 10y = 14

25x - 10y = -5

Subtract one of the new equations from the other

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x = -1

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Simplify the expression below
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Step-by-step explanation:

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2 years ago
Polly stacked the tins from five boxes of cat food onto an empty shelf in a supermarket. There were 15 tins of cat food in each
Alexandra [31]

Answer:

(a) 3\frac{2}{3} boxes of cat food had been sold.

(b) \frac{11}{3} boxes of cat food had been sold.

Step-by-step explanation:

From the question,

Polly stacked the tins from five boxes of cat food onto an empty shelf and there were 15 tins of cat food in each box. That is,

5 × 15 tins of cat food were stacked onto the empty shelf.

5 × 15 = 75

Hence, 75 tins of cat food were stacked onto the empty shelf.

Also, from the question,

At the end of the week there were 20 tins left on the shelf and the rest of the tins had been sold, that is

75 - 20 tins had been sold

75 - 20 = 55

Hence, 55 tins of cat food had been sold.

To determine the number of boxes of cat food that had been sold,

Since there are 15 tins of cat food per box, then

we will divide 55 tins of cat food that had been sold by 15 tins of cat food per box

55 ÷ 15 = \frac{55}{15}

Hence, \frac{55}{15} boxes of cat food had been sold

(a) As a mixed number

\frac{55}{15}  = 3\frac{2}{3}

Hence, 3\frac{2}{3} boxes of cat food had been sold.

(b) As an improper fraction

\frac{55}{15}  = \frac{11}{3}

Hence, \frac{11}{3} boxes of cat food had been sold.

7 0
3 years ago
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