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asambeis [7]
3 years ago
9

What is the midpoint of the line segment with endpoints ( 3.5,2.2) and (1.5,-4.8)?

Mathematics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

Option A) (2.5,-1.3) is correct

The midpoint of the given line segment is M=(2.5,-1.3)

Step-by-step explanation:

Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)

To find the mid point of these endpoints midpoint formula is M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Let (x_1,y_1) be the point (3.5, 2.2) and (x_2, y_2) be the point (1.5, -4.8)

substituting the points in the formula

M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

M=\left(\frac{3.5+1.5}{2}, \frac{2.2-4.8}{2}\right)

=\left(\frac{5}{2}, \frac{-2.6}{2}\right)

=\left(2.5,-1.3\right)

Therefore M=(2.5,-1.3)

The midpoint of the given line segment is M=(2.5,-1.3)

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Answer:

0.00008 (X^4 + 250000) is the answer

Step-by-step explanation:

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5.392 rounded to the nearest hundredths
pashok25 [27]
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Determine the equation of the line that is perpendicular to the lines r​(t) equalsleft angle6​t,1 plus3 ​t,4tright angle and R​(
Lynna [10]

\vec r(t)=\langle6t,1+3t,4t\rangle

\vec R(s)=\langle2+s,-8+3s,-12+4s\rangle

Take the derivatives of each to get the tangent vectors:

\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=\langle6,3,4\rangle

\dfrac{\mathrm d\vec R(s)}{\mathrm ds}=\langle1,3,4\rangle

Take the cross product of the tangent vectors to get a vector that is normal to both lines:

\langle6,3,4\rangle\times\langle1,3,4\rangle=\langle0,-20,15\rangle

The two given lines intersect when \vec r(t)=\vec R(s):

\langle6t,1+3t,4t\rangle=\langle2+s,-8+3s,-12+4s\rangle\implies t=1,s=4

that is, at the point (6, 4, 4).

The line perpendicular to both of the given lines through the origin is obtained by scaling the normal vector found earlier by \tau\in\Bbb R; translate this line by adding the vector \langle6,4,4\rangle to get the line we want,

\vec\rho(\tau)=\langle6,4,4\rangle+\langle0,-20,15\rangle\tau

\boxed{\vec\rho(\tau)=\langle6,4-20\tau,4+15\tau\rangle}

6 0
2 years ago
Here is a list 31 29 33 37 43 38 33 40 find the mode in number of list and work out on mean
Ede4ka [16]

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Step-by-step explanation: The mode is whatever number appears the most.

To find the mode, first put the numbers in order from least to greatest.

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In this case, 33 appears the most, so the mode is 33.

The mean is the average of all of the numbers.

Firstly, add up all of the numbers:

29 + 31 + 33 + 33 + 37 + 38 + 40 + 43 = 284

Now that you have all of them added up, divide the final sum by the number of numbers you have in the list. In this case, you have 8 numbers.

284/8 = 35.5

Your mean is 35.5

8 0
3 years ago
Read 2 more answers
a rectangular patio has a perimeter of 60 feet. if the length of the patio is 3 feet less than twice the width, find the dimensi
Juli2301 [7.4K]
P = 2(L + W)
P = 60
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60 = 2(2W - 3 + W)
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11 = W <=== the width is 11 ft

L = 2W - 3
L = 2(11) - 3
L = 22 - 3
L = 19 <=== the length is 19 ft
6 0
3 years ago
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