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3 years ago

6

Please just this couple of questions. Help me pleaseee

1 answer:

miskamm [114]3 years ago

8 0

Page 1 is B, page 2 is B, page 3 D, page 4 D ( prity sure not 100%), page 5 you posted it twice

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What is the 30th term of the linear sequence below?<br><br> -5,-7,-9,-11,-13....

adelina 88 [10]

Answer:

-63

Step-by-step explanation:

This arithmetic progression

The formula is a+(n-1)d

a means the first value

n is the nth term

d is the difference

So a is -5

n is 30

d is -2

So let's substitute

-5+(30-1)-2

-5+(29)-2

-5-58

-63

Therefore the final answer is-63

Just follow the step and the general formula, you will get your final answer

3 0

3 years ago

Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north

Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

$x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]$

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

Child 1 final position => $x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t$
Child 2 final position => $x_{2f} =0+v_{2} t$

4) Sum the equations and equate to 3

$x_{1f} +x_{2f} =3$

5) Substitute the values we already know

$1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]$

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0

3 years ago

Can someone answer this question please WBA’s wee it correctly if it’s correct I will mark you brainliest

oksano4ka [1.4K]

Answer:

$\frac{1}{6}*\frac{4}{13}$

Step-by-step explanation:

A 6 sided die has 6 outcomes.

Your sister picks from a 13 - slice plate meaning the fact that there are 13 outcomes.

There are 4 yellow slices so picking a yellow slice has a $\frac{4}{13}$ chance

You need to mutiply both displayed values to solve this problem.

$\frac{1}{6}*\frac{4}{13}$

6 0

3 years ago

Suppose that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective. Consider randomly selecting thre

Andrew [12]

Answer:

Step-by-step explanation:

Given that a box contains 45 light bulbs, of which 36 are good and the other 9 are defective.

Probability for any one to be defective as of now is $\frac{36}{45} =0.80$

a) $P(E) = 0.80$

b) After I draw we have 35 good ones and 9 defective

P(F/E) = $\frac{35}{44} \\=0.796$

c) P(G/EF)

This is the probability for iii bulb to be good given I and II are goog.

Once I and ii are good we have 43 bulbs with 34 good ones

$P(G/EF) =\frac{34}{43} \\=0.7907$

5 0

2 years ago

Find the distance between (2, 2) and (-4, 4). Round answer to the nearest tenth.

Naya [18.7K]

Answer:

6.3

Step-by-step explanation:

First off, we need the distance formula, which is:

$\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

If we plug in the points, we get:

$\sqrt{(-4 - 2)^2 + (4 - 2)^2}$

If we simplify everything under the square root, we get:

$\sqrt{(-6)^2 + (2)^2}$

$\sqrt{36 + 4}$

$\sqrt{40}$

In decimal, the answer is 6.3

6 0

3 years ago