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const2013 [10]
3 years ago
9

HELP WITH MATH!! RLLY COULD USE IT

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0

Answer:

120 square units

Step-by-step explanation:To find the area you do length times hight or l x h. If you want you can also make the triangle and move it to the other side to create a square if thats helps :) but you always do LxH for area :)

Alborosie3 years ago
7 0

Answer:

120

Step-by-step explanation:

Since it's a parallelogram, it has to be A = BH.

Base in this problem: 10

Height in this problem: 12

10x12=120

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Step-by-step explanation:

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3 years ago
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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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givi [52]
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Step-by-step explanation:

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Answer:

where is the expression??

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