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3 years ago

4.52*10^-3 mol of C20H42

Chemistry

1 answer:

kotegsom [21]3 years ago

8 0

1.27g

Explanation:

Given parameters:

Number of moles of C₂₀H₄₂ = 4.52 x 10⁻³moles

Unknown:

Mass of the compound = ?

Solution:

The mole is a comfortable unit for measuring chemical substances.

number of moles = $\frac{mass}{molar mass}$

Molar mass of C₂₀H₄₂ = (12 x 20) + (1 x 42) = 240 + 42 = 282‬g/mol

Mass of the compound = number of moles x molar mass

= 4.52 x 10⁻³ x 282

= 1.27g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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Answer:

$\boxed{\text{0.50 mol/L}}$

Explanation:

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1. Set up an ICE table

$\begin{array}{ccccc}\rm 2COF_{2} & \, \rightleftharpoons \, & \rm CO_{2} & +&\rm CF_{4}\\2.00& & 0& & 0\\-x& & +x & & +x\\2.00 - x& & x & &x \\\end{array}$

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$K_{c} = \dfrac{[\rm CO][ \rm CF_{4}]}{[\rm COF_{2}]^{2}} = 9.00\\\\\begin{array}{rcl}\dfrac{x^{2}}{(2.00 - x)^{2}} & = & 9.00\\\dfrac{x}{2.00 - x} & = & 3.00\\x & = &3.00(2.00 - x)\\x & = & 6.00 - 3.00x\\4.00x & = & 6.00\\x & = & \mathbf{1.50}\\\end{array}$

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$\text{The equilibrium concentration of COF$_{2}$ at equilibrium is $\boxed{\textbf{0.50 mol/L}}$}$

Check:

$\begin{array}{rcl}\dfrac{1.50^{2}}{0.50^{2}} & = & 9.00\\\\\dfrac{2.25}{0.25}& = & 9.00\\\\9.00 & = & 9.00\\\end{array}$

OK.

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4 years ago