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4 years ago

A _____ activation energy is required to break the double bonds of unsaturated hydrocarbons.

Chemistry

2 answers:

nadezda [96]4 years ago

8 0

Answer: High activation energy is required.

Explanation:

Unsaturated hydrocarbons are defined as the hydrocarbons in which double or triple bonds are present between two adjacent carbon atoms. They are known as alkenes and alkynes respectively. The general formula for these hydrocarbons is $C_nH_{2n}$ and $C_nH_{2n-2}$

In unsaturated hydrocarbons, more number of bonds are formed, thus the bond strength of the bonds formed will be more because the orbitals come closer to each other.

As, bond strength of unsaturated hydrocarbons are more. So, more energy will be required to break the bond between them.

Hence, high activation energy is required.

Olegator [25]4 years ago

3 0

Small. small is the answer assuming you are on usatestprep

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Do sample problem 13.8 in the 8th ed Silberberg book. You add 1.4 kg of ethylene glycol (C2H6O2) antifreeze to 4,192 g of water

zmey [24]

Answer:

The solution boils at 102.76 °C

Explanation:

Δt = m* Kb x i

i = 1 with 1 particle in solution

m = molality

Kb = 0.512 °C/molal

Step 2: Calculate moles C2H6O2

molar mass of C2H6O2 = 62.068 g/mol

Calculate number of moles:

Moles = Mass / molar mass

Moles = 1400 grams / 62.068 g/mol

Moles C2H6O2 = 22.56 moles

Step 3: Calculate molality

these are in 4192 g of water:

22.56 moles / 4.192 kg water

⇒ moles / kg of water = 5.38 moles / Kg = m olal

Step 4: Calculate ΔT

ΔT= Kb * molal = 5.38 molal* 0.512 °C/m

ΔT = 2.76 °C

Boiling point = 100°C + 2.75 °C = 102.76 °C

the solution boils at 102.76 °C

7 0

3 years ago

45 grams of ammonia, NH3, in 0.75 L of solution.

GrogVix [38]

2.3 moles of sodium chloride in 0.45 liters of solution . necessarile correct ... 0.025 L. (1.3 SF). 45 grams of ammonia in 0.75 L of solution. 45g x 1 mol = 2. demol ... anol x 1,50 = 3 mol NaOH x 40,019 = 120g Naolt.

4 0

4 years ago

What happens to energy when frequency

Law Incorporation [45]

Answer:

Energy is halved.

Explanation:

Energy and Frequency are directly proportional. If frequency decreases, energy increases. If frequency increases, energy increases. If frequency is halved, energy is also halved.

8 0

4 years ago

8. The standard enthalpy of formation of RbF(s) is –557.7kJ/mol and the standard enthalpy of formation of RbF(aq, 1 m) is –583.8

garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7) kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

3 0

3 years ago

The standard free energy change for a reaction can be calculated using the equation

snow_lady [41]

Answer:

a) 1,737 kJ

b) -1,93 kJ

Explanation:

The standard free energy change (ΔG) can be determined using:

ΔG = -nFE

a) For the reaction:

Fumarate²⁻ + CoQH₂ ⇄ succinate²⁻ + CoQ

The transferred electrons are 2, As E=-0,009V:

ΔG = -2×96,5kJ/molV×-0,009V

ΔG = 1,737 kJ

b) For the reaction:

cytc1 (Fe²⁺) + cytc (Fe³⁺) ⇄ cytc1 (Fe³⁺) + cytc (Fe²⁺)

The transferred electron is n=1 and E=0,02V:

ΔG = -1×96,5kJ/molV×0,02V

ΔG = -1,93 kJ

I hope it helps!

7 0

4 years ago