Answer:
Hope this helps :)
Step-by-step explanation:
15
(3^5)÷(3^5)
Simplify 3^5
243÷243
1
(3^5)÷(3^5)
3^5/3^5=3^5-5
3^5-5
3^5-5= 1
1
Formula: x^a/x^b=x^a-b
16
2^10/2^10
Cancel out 2^10
1
2^10/2^10
2^10/2^10=2^10-10
2^10-10
2^10-10=1
1
Formula: x^a/x^b=x^a-b
17
x^7/x^7x≠0
x≠0
18
(4x+2y)5÷(4x+2y)^5(4x+2y) ≠ 0
5/(4x+2y)^3 ≠ 0
5 ≠ 0
≠ =-y/2
19
No solution
20
p^4/p^4p ≠ 0
p≠ 0
no solution
Step 1. Identify the variable.
Step 2. Write an algebraic equation.
Step 3. Solve the equation.
Step 4. Answer the equation.
Step 5. Check answer.
Hope this helps...?
Answer:
The answer is 18.2.
Step-by-step explanation:
Answer:
Expected value would be $ 0.896
Step-by-step explanation:
Given,
The price of the lottery ticket = $44800000,
Also, the probability of winning the grand prize = .000000020,
Thus, the expected value of the lottery ticket = value of the lottery ticket × probability of getting the lottery ticket
= 44800000 × .000000020
= $0.896
Note : value of lottery ticket = prize amount - cost of each ticket,
Here the cost price of a ticket is not given,
That's why we did not consider it.
Answer:
Area of model pond = 45.6 inch² (Approx.)
Step-by-step explanation:
Given:
Circumference of circular pond = 24 inches
Find:
Area of model pond
Computation:
Circumference of circle = 2πr
Circumference of circular pond = 2πr
24 = 2[22/7][r]
Radius r = [24 x 7] / [2 x 22]
Radius r = 3.81 inch (Approx.)
Area of circle = πr²
Area of model pond = πr²
Area of model pond = (22/7)(3.81)²
Area of model pond = [3.1428][14.5161]
Area of model pond = 45.6 inch² (Approx.)
