Answer:
A.) 20x + 2y = 500
B.) y-intercept = 250; its meaning is how many boxes of pencils they started with.
C.) x-intercept = 25; How many T-shirts they can sell at most
Step-by-step explanation:
2y - 500 = -20x
20x + 2y - 500 = 0
20x + 2y = 500
y-intercept = 250; its meaning is how many boxes of pencils they started with.
20x + 2y = 500
20(0) + 2y = 500
2y = 500
2y/2 = 500/2
y = 250
x-intercept = 25; How many T-shirts they can sell at most
20x + 2y = 500
20x + 2(0) = 500
20x = 500
20x/20 = 500/20
x = 25
Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
__
The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
Answer:
ΔLMN ≅ ΔLQP by (SAA)
Step-by-step explanation:
It is given that line (NM) is congruent to the line (PQ), meaning they have the same measure. This is signified by the small red line on each of these sides.
Moreover, it is also given that angle (MNL) is congruent to angle (QPL), this is shown by the red arc around these angles.
Finally one can figure out that angle (NLM) is congruent to angle (PLQ) by the vertical angles theorem. The verticle angles theorem states that when two lines intersect, the opposite angles are congruent.
Thus the two triangles are congruent by side-angle-angle postulate, abbreviated as (SAA).
