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Ymorist [56]
3 years ago
15

Which fraction is between – 3/8 and –9/16 on a number line?

Mathematics
1 answer:
prohojiy [21]3 years ago
4 0

Answer:

-7/16 & -8/16 (which is -1/2)

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Given csc A= 37/12 and that angle A is in Quadrant I, find the exact value of sec A in
vredina [299]

Answer:

Step-by-step explanation:

Below is the pic of how this would be set up in order to determine what it is you are looking for. The angle is set in QI, and since csc A is the reciprocal of sin, the ratio is hypotenuse over side opposite. Solve for the missing side using Pythagorean's Theorem:

37^2=12^2+b^2 and

1369 = 144 + b² and

1225 = b² so

b = 35

The sec ratio is the reciprocal of cos, so if cos is adjacent over hypotenuse, the sec is hypotenuse over adjacent, which is 37/35

7 0
3 years ago
A rectangular balcony has an area of 32 square feet. its perimeter is 24 feet. what are the dimensions of the balcony?
Paul [167]

Answer:

Step-by-step explanation:

8 ft by 4 ft

8ft x 4ft = 32 ft

8ft + 8 ft = 16 ft  4 ft + 4 ft = 8 ft

16ft + 8 ft = 24 ft

5 0
3 years ago
0.136363636 as a fraction
Alex787 [66]

Answer:

0.136363636 = 34090909 / 250000000

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
How many three-letter "words" can be made from 9 letters "fghijklmn" if repetition of letters (a) is allowed?
11Alexandr11 [23.1K]
729. You just do 9 to the power of 3 or 9^3 and you will get 729. If it is not allowed, the answer is 504.(9 x 8 x 7)
8 0
3 years ago
A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Lyrx [107]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

                                                 =( \pi \times 2^2\times h)\ m^3

\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

3 0
2 years ago
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