Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147
Answer:
D
Step-by-step explanation:
Here, we want to select which of the options explains the scenario in the question.
Firstly, 1,000 shares were purchased at $10 per share.
Mathematically the total amount of shares bought will be 10 * 1000 = $10,000
Also, we have the growth rate as 12.5% = 12.5/100 = 0.125
Thus, representing the scenario with a function, we have;
A(t) = 10,000 e0.125t
Answer:
f(12) = 9
x = 0 when f(x) = 5
Step-by-step explanation:
The answer is 16773.6 because you just find the 34.8 percent of 48,200
Well, since you have the value of b, the first thing you want to do is substitute that value in for b.
5a - 10(3) = 45
10*3 = 30
5a - 30 = 45
Now, to get the variable by itself (a) you have to + 30 because you have to reverse the subtraction.
5a = 75
Now, you divide by 5 to finish getting a by itself.
a = 15
Hope this helps!
