Help me please,Thanks;)

Mathematics

1 answer:

Lunna [17]3 years ago

6 0

I think that the base of this parallelogram is 13.6 cm. I may be wrong though. Double check the work. Divide area by width and you'll get the length.

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Simplify (4x^4y^3)^3/3(5x^2y^6)^2

jolli1 [7]

Answer: Hence, our simplified form will be :

$\frac{64}{75}x^8y^{-3}$

Step-by-step explanation:

Since we have given that

$\frac{(4x^4y^3)^3}{3(5x^2y^6)^2}$

We need to simplify the above expression:

$\frac{(4x^4y^3)^3}{3(5x^2y^6)^2}\\\\=\frac{4^3x^{4\times 3}y^{3\times 3}}{3\times 5^2x^{2\times 2}y^{6\times 2}}\\\\=\frac{64x^{12}y^9}{3\times 25x^4y^{12}}\\\\=\frac{64x^{12}y^9}{75x^4y^{12}}\\\\=\frac{64}{75}x^{12-4}y^{9-12}\\\\=\frac{64}{75}x^8y^{-3}$

Hence, our simplified form will be :

$\frac{64}{75}x^8y^{-3}$

5 0

2 years ago

Solve: logx64 = 3 which is an equivalent equation?

zepelin [54]

By applying the definition of logarithm, you have

$\log_x(64) = 3 \iff x^3 = 64$

So, if you consider the cubic root of both sides, you have

$x = \sqrt[3]{64} = 4$

4 0

2 years ago

Read 2 more answers

AC is the diameter. Calculate the area of the sector (to the nearest whole number) created by ∠CDB.

TiliK225 [7]

Area of the circle is πr² which corresponds to an angle of 360° subtended at the center. Thus, the area of a sector subtending angle $\theta$ at the centre is: