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ch4aika [34]
3 years ago
8

If The Atlanta Falcons scored 4 touchdowns and 3 field goals and the Packers scored 3 touchdowns and 4 field Goals who would win

?
Mathematics
2 answers:
Lana71 [14]3 years ago
6 0

Answer:

1+1= 11

Step-by-step explanation:

Mashcka [7]3 years ago
4 0

Answer:

Atlanta Falcons would win

Step-by-step explanation:

A touchdown is six points

A field goal is three points

Atlanta Falcons: 4x6=24 & 3x3=9

Packers: 3x6=18 & 4x3=12

Atlanta Falcons: 24+9=33

Packers:18+12=30

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mojhsa [17]
Hey You!

16 - 20 / 16 * 100 = 25

The percentage increase from 16 to 20 is 25%. =)
6 0
3 years ago
of the 50 U.S states, 4 have names that start with the letter W. What percentage of U.S. states have names that start with the l
serious [3.7K]

Answer:

8% of of the Us states have the names that start with W.

Step-by-step explanation:

We are told that, of the 50 states, 4 have names that start with letter W, and to figure out what percentage of U.S. states have names that start with the letter W, we need to know what what 4 is what percent of 50.

We figure this out the following way:

Percent = \frac{4}{50} *100=0.08*100 =8

Percent = 8%

6 0
3 years ago
Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
How do I simplify this??
alina1380 [7]
Idk i can't see that, sorry
8 0
3 years ago
For a school play, Josh bought 3 adult tickets and 5 child tickets for $40. Emily bought 1 adult ticket and 5 child tickets for
lana [24]
The cost for an adult and child are both $5
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