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Natalka [10]
2 years ago
11

Basketball has a radius of 3.4in, how much air can it hold?

Mathematics
1 answer:
Burka [1]2 years ago
3 0
Volume of a sphere is (4/3)(pi)(r)^2 if r is 3.4 than the answer would be 24.65333pi or about 77.4115
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Strawberries are $3.99 per pound. If a customer bought $30 worth, how many pounds did he buy? $
lubasha [3.4K]

Answer:

7.5

Step-by-step explanation:

Divide 30 by 3.99

  • 30/3.99=7.5
3 0
2 years ago
Which ordered pair is a solution of the equation y= -5x +4......(2,14) (5, -29) (3, -19) (5, -21)
Ratling [72]

1) 2x+4y=10
3x+5y=14 .

find d2, dx2, and dy

2) Solve the system of equations algebraically and show your work.

2x + 3y = 12
2x - y = 4

3) Which of the ordered pairs (5,5),(5,0) and (-3,2) can be found in the shaded solution area for the system of inequalities below? (The ordered pair must be in the double shaded region or it is not a solution of the system.)

x+2y<6
2x+y > or equal too 9 so yea hoped this helped


6 0
3 years ago
How do I find the slope-intercept form that has <br> Slope: -1 Point: (2,-3)
Alenkasestr [34]

y - (-3) = -1(x - 2)

y + 3 = -1(x - 2)

y + 3 = -x + 2

y = -x - 1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
An animal shelter spends $5.50 per day to care for each bird and $8.50 per day to care for each cat. Anna noticed that the shelt
Mama L [17]

Answer:

19

Step-by-step explanation:

We can solve this problem using a system of equation in two unknowns.

Let b = number of birds.

Let c = number of cats.

The care of a bird costs $5.50, so for b number of birds, the cost of care is 5.5b.

The care of a cat costs $8.50, so for c number of cats, the cost of care is 8.5c.

The total cost of care for the birds and cats is 5.5b + 8.5c.

The total cost of care is $291.50. This must equal the expression we have above, so we get our first equation.

5.5b + 8.5c = 291.5

The total number of birds and cats is b + c, but we are told it is 41, so our second equation is:

b + c = 41

We now have the following system of two equations in two unknowns.

5.5b + 8.5c = 291.5

b + c = 41

Rewrite the first equation.

Multiply both sides of the second equation by -8.5, and write it under the first equation. Then add the equations.

      5.5b + 8.5c = 291.5

+    -8.5b - 8.5c = -348.50

--------------------------------------

        -3b            = -57

Divide both sides of the equation by -3.

b = 19

Answer: there were 19 birds

4 0
3 years ago
a right angled triangle has sides which are 2cm and 7cm shorter than its hypotenuse find the length of the hypoenuse
vekshin1

Answer:

The length of the hypotenuse side is (9 + 2·√7) cm

Step-by-step explanation:

The given parameters of the triangle are;

The type f triangle = Right triangle

The length of the sides 2 cm and 7 cm shorter than the hypotenuse

Let 'h' represent the length of the hypotenuse side of the triangle, in centimeters we have;

The length of one side of the right triangle = (h - 2) cm

The length of the other side of the right triangle = (h - 7) cm

By Pythagoras's theorem, we have;

h² = (h - 2)² + (h - 7)²

Using search function on the internet, we have;

h² = (h - 2)² + (h - 7)² = 2·h² - 18·h + 53

∴ h² = 2·h² - 18·h + 53

∴ 2·h² - 18·h + 53 = h²

h² - 18·h + 53 = 0

53 is a prime number, therefore, by the quadratic formula, we have;

h = (18 ± √((-18)² - 4×1×53))/(2 × 1)

h = 9 + 2·√7 cm ≈ 14.29 cm or h = 9 - 2·√7 ≈ 3.71

However, given that one of the side is 7 cm shorter than the hypotenuse, for all the sides to remain positive, we have h = 9 + 2·√7 cm ≈ 14.29 cm , because for h ≈ 3.71 cm, we have;

The length of the other side = (h - 7) cm ≈ (3.71 - 7) cm ≈ -3.29 cm which is not possible for a real triangle

Therefore, the length of the hypotenuse side, h = 9 + 2·√7 cm ≈ 14.29 cm.

5 0
2 years ago
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