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pickupchik [31]
3 years ago
13

2-1. Point A is at elevation 2690 feet and is located 520 feet due north of point B which is at elevation 2220 feet. Point C is

at elevation 2340 feet and is located 250 feet N35°E of point B. What are the strike and dip of a unit whose upper surface was observed at each of these points?
Geography
1 answer:
meriva3 years ago
7 0

Answer:

In the given topography, point A is the northern side at a height of 2690 feet. B is at a height of 2220 feet and location C has a height of 2340 feet. A and B are separated by a horizontal distance of 520 feet, B and C are separated by a horizontal distance of 250 feet and C is located at N35°E of point B.

From the above data, we can demarcate the topography of the area. The area is inclined towards the southern side as when we move from point A to C and C to A the elevation gradually decreases.

Thus, <u>the exposed rock unit in that area dips towards the South and the strike direction of this rock is the East-west direction.</u>

Dip is defined as the angle made by a rock bed with respect to a horizontal line and strike refers to the direction of the line that is formed due to the intersection between a rock surface and a horizontal plane.

Dip and strike always perpendicular to one another.

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