Answer:
Step-by-step explanation:
<u>Given GP with </u>
<u>Let the common difference is r, then</u>
<u>Solve for r and then a₁:</u>
- 4r = 7 ⇒ r = 7/4
- a₁(7/4)³ = 4
- a₁ = 4*(4/7)³ = 4⁴/7³ = 256/343
If two cords are the same distance from the center of a circle than both cords are congruent
<span>So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V=(1/3)*pi*r^2*h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1=(1/3)*pi*(r1^2)*h1 - (1/3)+pi*(r2^2)*h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.</span>
If a^2 + b^2 = c^2 then it is a right triangle.
22^2 + 26^2 ?=? 34^2
484 + 676 ?=? 1156
1160 ?=? 1156
This is NOT TRUE so it is not a right triangle.