The answer to your question is c
The graph y=|x|-4 is obtained from the graph y=|x| dy <span>moving down 4 units the graph y=|x| along the y-axis (see, if x=0, then for y=|x|, y=0 and for y=|x|-4, y=-4).
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These two graphs have the same form.
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1) When the denominator equals zero that is a critical point
=> x - 2 = 0 => x = 2.
So x = 2 is a critical point
2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)
Multiply both terms:
[2x + 5] / [ x - 2] = [x - 1] / [x - 2]
for x ≠ 2 => 2x + 5 = x - 1
=> 2x - x = - 1 - 5
=> x = - 6
Then, the two critical points are x = 2 and x = - 6.
Answer: option B.
Answer:
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Step-by-step explanation:
3 + 5 =7
For the answer to the question above asking to f<span>ind the coordinates of Z without using any new variables.
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Vector WZ equals vector VP, which is (p, -q)
So Z is (-p - r + p, q - q) which is (-r, 0)
I hope my answer helped you.