Question

The ten students in a club are lined up in a row for a group photograph. How many different arrangements are possible if the club includes one set of identical triplets wearing matching clothes?

Answer 1

We know that

if the club includes one set of identical triplets wearing matching clothes

then

the number of different arrangements that are possible is

10! / 3! = (10*9*8*7*6*5*4*3!)/3!

=604,800

The answer is

604,800

Answer 2

Answer:

604,800 different arrangements.

Step-by-step explanation:

The number of ways 10 objects can be arranged normally is 10!

It if there were 3 identical objects that all look similar, a number of the arrangements obtained for 10 objects will end up being similar, we account for this condition by dividing the total number of arrangements by the number of ways those 3 identical objects can be arranged on their own; 3!

So, for this question, the number of arrangements of 10 students possible if it includes one set of identical triplets wearing matching clothes will be

(10!/3!) = 604,800 different arrangements.

Hope this Helps!!!