(z + 6) / 3 = 2z / 4
this is a proportion, so we cross multiply
(3)(2z) = 4(z + 6)
6z = 4z + 24
6z - 4z = 24
2z = 24
z = 24/2
z = 12 <==
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
The highest common factor for both 102 and 153 is
GCF- 51
Step-by-step explanation:
51*3= 153
51*2=102
Answer:
<u>The answer is -4 3/5</u>
Step-by-step explanation:
Let's reduce to its simplest form:
-3/5 + (-8/2) =
Step 1: Lowest Common Denominator (10):
- 6/10 + (-40/10) =
Step 2: Solve the parentheses:
- 6/10 - 40/10 =
Step 3: Subtract the fractions:
-46/10
Step 4: Simplify (Dividing by 2):
-23/5
Step 5: Converting the fraction to mixed number:
-4 3/5
<u>The answer is -4 3/5</u>