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Solnce55 [7]
3 years ago
7

Find the difference between the points (2.7, 5.1) and (3, 4.7) please :)

Mathematics
2 answers:
malfutka [58]3 years ago
4 0
B. 0.5 hope u get a good grade
SCORPION-xisa [38]3 years ago
3 0
I would use the distance formula: d=√(x2-x1)^2+(y2-y1)^2
(2.7, 5.1) is the first point and (3, 4.7) is the second point
d=√(3-2.7)^2+(4.7-5.1)^2
d=√(.3)(.3)+(-.4)(-.4)
d=√0.09+0.16
d=√0.25
d=0.5 so B

Hope this helps
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Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

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First, we shall simplify the given expression.

Thus, we have,

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Expanding the expression, we have,

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Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

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Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

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