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Dennis_Churaev [7]
3 years ago
14

Mick paid 2.94 in sales tax on an item that costs 42 dollars before tax. At that rate how much would he pay in sales tax for an

item that costs 58.00
Mathematics
2 answers:
djverab [1.8K]3 years ago
4 0
Mick would pay $4.06 in sales tax for an item that costs $58.00.

This can be found by working backwards in the problem. By dividing that sales tax paid (2.94) by the dollars before tax (42), you get a percentage that should equal the percentage of the total paid for tax.

2.94 ÷ 42 = 0.07

This means that the sales tax is 7% of the total prior to tax. So we'd then multiply our dollars (58) with the sales tax in decimal form (0.07)

58.00 × 0.07 = 4.06

Hope I could help!
dybincka [34]3 years ago
4 0
<u>Find Sales Tax Rate:</u>

\text {Sales Tax Rate} =  \dfrac{\text{Sales Tax}}{\text{Original}} \times 100

\text {Sales Tax Rate} =  \dfrac{2.94}{42} \times 100 = 7\%

<u>Find tax for an item that cost $58:
</u>
\text {Sales Tax Rate} = 7\% \text{ of } \$58 = \dfrac{7}{100} \times 58 = \$4.06

Answer: Sales Tax = $4.06
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Write the set of points from  -6 to 0 but excluding  -4  and 0 as a union of intervals

First we take  the interval  -6 to 0. In that -4  and 0 are excluded.

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The cargo carrying part of Billy‘s truck has a length of 8.3 m a width of 3 m and a height of 4.2 m. What is the maximum volume
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In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct
kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

                  =(0.93\times0.03)+(0.10\times0.97)\\=0.1249

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

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3 years ago
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