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Kipish [7]
3 years ago
11

Rename 40,000 using other place values

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0
40 thousands, 0 hundreds, 0 tens, 0 ones
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grandma gigi gave leyla a rare purple stone for her sweet 16 birthday. at that time,the stone was worth$245. it has been increas
sergij07 [2.7K]
This is a compound interest problem, therefore s(t) should be in the form:
s(t) = a(r)^{t}

where: 
t = time in years
s(t) = the value of your item after t years
a = the initial value of your item
r = rate

Therefore, we already know that a = 245$.

Now, we can calculate r:
r^{t}=\frac{s}{a}
r =  \sqrt[t]{ \frac{s}{a} }
r = \sqrt[5]{ \frac{560.50}{245} }
     = 1.18

Therefore, the correct answers are a = 245 and r = 1.18

4 0
3 years ago
The net of a cylinder is shown. The area of one base of the cylinder is 9Pi in.2. The circumference of a base is 6Pi in., and th
hram777 [196]

Answer:

9Pi + 9Pi + 6Pi(10) in.^2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
2 - 1/4 in simplest form PLS HURRYYYY
gavmur [86]

Answer:

The answer is 1.75

Step-by-step explanation:

2-1/5 or (.25)

8 0
2 years ago
Mattie uses the discriminant to determine the number of zeros the q
enot [183]

Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac

there are 3 basic cases of what happens for different discriminants

1. if the discriminant is less than 0, then there are no real zeroes

2. if the discriminant is 0, then it has 1 zero

3. if the discriminant is greater than 0, it has 2 zeroes

so given

0=3x^2-7x+4

a=3,b=-7,c=4

thus the discriminant is (-7)^2-4(3)(4)=49-48=1

the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0

the answer is the equation has two zeroes because the discriminant is greater than 0

Step-by-step explanation:

3 0
3 years ago
Thirty-three college freshmen were randomly selected for an on-campus survey at their university. The participants' mean GPA was
Ivan

Answer: \pm0.1706

Step-by-step explanation:

Given : Sample size : n= 33

Critical value for significance level of \alpha:0.05 : z_{\alpha/2}= 1.96

Sample mean : \overline{x}=2.5

Standard deviation : \sigma= 0.5

We assume that this is a normal distribution.

Margin of error : E=\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. E=\pm (1.96)\dfrac{0.5}{\sqrt{33}}=\pm0.170596102837\approx\pm0.1706

Hence, the  margin of error is \pm0.1706

7 0
3 years ago
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