2*10^6 + 6*10^5 + 3*10^3 +9*10^1 +4*10^0
see expanded form is adding the digits together. and it would be what ever one number is times 10 to the power of how many digits are after that number. you skip the 0's though. hope this helps
System A has ONE real solution
System B has NO real solutions
System C has ONE real solution
Answer:
Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.
Step-by-step explanation:
✔️Function A:
Initial value = y-intercept (b)
y-intercept is the value of y, when the corresponding value of x = 0
From the table, y = 6 when x = 0.
The y-intercept of function A = 6
Therefore, initial value for Function A = 6
✔️Function B:
y = 4x + 3 is given in the slope-intercept form, y = mx + b.
b = y-intercept = initial value.
Therefore
Initial value for Function B = 3
✔️Function A has the greater initial value because the initial value for Function A is 6 and the initial value for Function B is 3.
I donnt think that there is a solution, but could be wrong
Answer:
16.7
Step-by-step explanation:
We can use the Pythagorean theorem, a^2 + b^2 = c^2.
a = 11
c = 20
11^2 + b^2 = 20^2
121 + b^2 = 400
b^2 = 279
b = sqrt(279) = 16.7
