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Lubov Fominskaja [6]
3 years ago
5

When a third of a number is subtracted from a half of the same number, 60 is the result. Find the number

Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

the answer is 360 because if you take a third you will have 120 then if you take half of that then you get 60

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What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
Will give brainliest
Lisa [10]

Answer:

First Gardener.

Step-by-step explanation:

1st gardener= 56 divided by 8= 7 bushes <---

2nd gardener= 45 divided by 5= 9 bushes

3rd gardener= 80 divided by 10= 8

8 0
3 years ago
Read 2 more answers
I NEED HELP NOW!!!! Please this is Due!!
Sladkaya [172]

Answer:

85 quarters and 135 dimes

Step-by-step explanation:

its basically a guess and check

formula - 0.25q + 0.10d = $34.75

0.25 x 85 + 0.10 x 135 = 34.75

8 0
3 years ago
En red socks and ten blue socks are all mixed up in a dresser drawer. The 20 socks are exactly alike except for their colour. Th
Gennadij [26K]

Answer:

3 socks

Step-by-step explanation:

Given that, there are 10 red socks and 10 blue socks which are mixed up in the dresser drawer.

The socks are identical except the color.

We need to find out, the minimum number of socks to be taken out from the dark room so that there is at least a pair of matching socks comes out of the drawer.

Let us consider the cases:

First Two socks pulled out of the drawer.

Case 1: Both are red or both are blue.

In this case, the matching pair is ready.

But there can be other case as well.

Case 2:

One red and one blue color taken out.

Now, when we pull the third, there will be either red or blue.

That will make a pair.

Therefore, to cover up all the cases and to be certain to get a matching pair out of the drawer, <em>at least 3 socks must be taken out</em>.

So, the answer is:

We need to take out at least 3 socks.

5 0
3 years ago
Find the indicated probability. Round to three decimal places. The participants in a television quiz show are picked from a larg
Arturiano [62]

Answer:

0.033

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ (1−p)ⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Here, p = 0.5, q = 0.5, and n = 11.

We need to find P when r is 0, 1, and 2, then add up the results to get the total probability.

r = 0:

P = ₁₁C₀ (0.5)⁰ (0.5)¹¹⁻⁰

P ≈ 0.0005

r = 1:

P = ₁₁C₁ (0.5)¹ (0.5)¹¹⁻¹

P ≈ 0.0054

r = 2:

P = ₁₁C₂ (0.5)² (0.5)¹¹⁻²

P ≈ 0.0269

Therefore, the total probability is:

P = 0.0005 + 0.0054 + 0.0269

P = 0.0328

Round to the thousandths place, the probability is 0.033.

3 0
3 years ago
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