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3 years ago

Find the sum of the decimal models.

Mathematics

1 answer:

Kruka [31]3 years ago

5 0

8.3 is the decimal for the first model and for the second model it is 4.8. Now you just need to add them and you should get 13.1 as your answer. If helped mark me the brainiest!!

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There are 300 raffle tickets. The prizes are as follows: First prize - voucher for meal at local restaurant Second prize - food

Andru [333]

Answer:

2/299

Step-by-step explanation:

there were 300 tickets and 1 is out . 299 tickets left

There were 3 prizes and 1 is out. 2 prizes left.

The probability of winning ANY prize when next ticket is drawn is

P(prize) =2/299

6 0

3 years ago

How to be a successful student?

SashulF [63]

Answer:

If you want to be a successful student, read below! :)

Step-by-step explanation:

First, listen to the teacher.

Second, don't be late.

Third, don't talk back.

Fourth, don't be disrespectful.

Fifth, don't cause commotions on purpose.

Sixth, do your assignments/tests/quizzes on time

If your teacher is normal, then these tips should help, I am the top student in my class and this is what I do.

Hope this helped!

5 0

3 years ago

Read 2 more answers

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

5 0

3 years ago

Read 2 more answers

Help me! Read the question carefully

prohojiy [21]

Answer:

21mm

Step-by-step explanation:

The formula for solving the area of a rhombus is : $\frac{1}{2}xy$ , where x and y are two intersecting diagonals.

In this case, we are given both values, thankfully. 6 and 7 are to be replaced with x & y. Now, the rest you have to do is simple math.

$(6 * 7) / 2 = 21$

The area of the rhombus is 21mm.

5 0

3 years ago

My calculator does not have a 3 key that works! How can I use this broken calculator to do 23 x 45.

erik [133]

<h3><u>Solution:-</u></h3>

$\longrightarrow$ This problem can be tackled by using distributive property of multiplication .

It states for any three numbers a,b and c

$\green{ \underline { \boxed{ \sf{(a±b)\times c = a \times c±b\times c}}}}$

<u>Similarly</u>,

$\quad$ 23 × 45

$\longrightarrow$ (21+2) ×45

$\longrightarrow$ 21×45+2×45

$\longrightarrow$ 945 + 90

$\longrightarrow$ 1035

It can also be done as-

$\quad$ 23 × 45

$\longrightarrow$ (25-2) ×45

$\longrightarrow$ 25×45-2×45

$\longrightarrow$ 1125-90

$\longrightarrow$ 1035

3 0

2 years ago