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Korvikt [17]
3 years ago
12

487 times 46871 minus 587 plus 2 divid by 4 minus 6

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
487 x 46871 - 587 + 2 / 4 - 6 = 5706392 
When solving, make sure you use order of operations correctly.
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Answer:

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Step-by-step explanation:

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I need help <br> 22 points to whoever helps me
Olenka [21]

Answer:

12 3/4 same slope fro both

13 DE = 5, CB = 10

14 see below

Step-by-step explanation:

12.  the slopes are the same

D(0, 3)  E(4, 6) slope is (change in y)/(change in x)

   change in y = 3 to 6 is a change of +3

   Change in x = 0 to 4 is a change of +4

slope is 3/4

13  To fine lengths you can distance formula or Pythagorean theorem (spoiler: they are related to each other)  

DE² = 3² + 4²

DE² = 9 + 12

DE² =  25

√DE² = √25 = 5

DE = 5

and

CB² = 6² + 8²

CB² = 36 + 64

CB² = 100

√CB² = √100 = 10

CB = 10

14.   since the slopes are the same are DE is 1/2 or CB its is the mid segment.  because (taken from mathopenref.com/trianglemidsegment.html)

The midsegment is always parallel to the third side of the triangle. In the figure above, drag any point around and convince yourself that this is always true.

The midsegment is always half the length of the third side. In the figure above, drag point A around. Notice the midsegment length never changes because the side BC never changes.

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6 0
3 years ago
Use rounding to estimate the product of 5, 555 and 4, 444. Round both numbers to the nearest thousand to find your answer.
uranmaximum [27]

Step-by-step explanation:

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8 0
2 years ago
A tee-ball team for 5 year-olds has half as many girls as boys. If there are 15 children on the team, how many are boys and how
Usimov [2.4K]
There are 10 boys because half of 10 is 5 5+5 equals 10
4 0
3 years ago
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Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert
Setler [38]

Answer:

P(x \ge 5) = 1.000 ---- At least 5 from marketing departments are extroverts

P(x=15) = 0.013 ---- All from marketing departments are extroverts

P(x = 0) = 0.002 ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

(a):\ P(x \ge 5)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

Using the complement rule, we have:

P(x \ge 5) = 1 - P(x < 5)

So, we have:

P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)

P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}

P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}

P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}

P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153

P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103

So, we have:

P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103

P(x < 5) = 0.00011922283

Recall that:

P(x \ge 5) = 1 - P(x < 5)

P(x \ge 5) = 1 - 0.00011922283

P(x \ge 5) = 0.9998

P(x \ge 5) = 1.000 --- approximated

(b)\ P(x = 15)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}

P(x=15) = 1 * 0.75^{15} * (0.25)^{0

P(x=15) = 0.013

(c)\ P(x = 0)

n=5 ---------- computer programmers

p = 70\% --- proportion that are introverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}

P(x = 0) = 1 * 1 * (0.30)^5

P(x = 0) = 0.002

3 0
2 years ago
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