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Korvikt [17]
3 years ago
12

487 times 46871 minus 587 plus 2 divid by 4 minus 6

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
487 x 46871 - 587 + 2 / 4 - 6 = 5706392 
When solving, make sure you use order of operations correctly.
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On a coordinate plane, 2 right triangles are shown. The first triangle has points A (negative 1, 3), B (negative 1, 1), C (3, 1)
drek231 [11]

Answer:

  • B and E

Step-by-step explanation:

<u>Given</u>

  • ΔABC ⇒ A(- 1, 3), B(- 1, 1), C(3, 1)
  • ΔA'B'C' ⇒ A'(2, - 2), B'(2, - 4), C'(6, - 4)

<u>Comparing the coordinates of the corresponding vertices, we see the difference:</u>

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It means the ΔABC has been translated 3 units right and 5 units down

Correct answer choices are B and E

8 0
3 years ago
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Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.
likoan [24]

Let v be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}

where s_A,\ s_B are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if s_A=s_B, and we know that this happens after two hours, i.e. at t=2

\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450

Solving this equation for v we have

2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105

So, train A is travelling at 105 km/h. This implies that train B travels at

105\cdot \dfrac{8}{7} = 15\cdot 8=120 \text{ km/h}

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C so a proportional relationship
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