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Ivan
3 years ago
5

Please help asap!! I need to hand this in!! Need an accurate answer!!

Mathematics
1 answer:
brilliants [131]3 years ago
5 0

Answer:

-1/4 * 1/3 = -1/12

Step-by-step explanation:

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You know the distance between two cities is 140 miles. What is the distance in kilometers?
Juli2301 [7.4K]
The unknown is the distance in kilometres
The given is the distance in miles=140 miles
1 mile=1.6093km
140 miles=?
140/1*1.6093km=225.302km
Therefore the 140 miles in km is 225.302km
7 0
3 years ago
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Please need help i need help i need help
xeze [42]

Set each expression from the parentheses equal to 0 separately like so:

Equation 1: x - 4 = 0

Equation 2: -5x + 1 = 0

Now for each equation solve for x!

Equation 1:

x +(- 4 + 4) = 0 + 4

x = 4

Equation 2:

-5x +( 1-1) = 0 - 1

-5x/ -5 = -1 / -5

x = 1/5

Check:

(4 - 4)(-5*4 + 1)

(0) (-20 + 1)

(0) (-19)

0 = 0 -------------------------> correct!

(1/5 - 4)(-5 * 1/5 + 1)

(-19/5)(-1 + 1)

(-19/5)(0)

0 = 0 -------------------------> correct!

smaller x = 1/5

larger x = 4

Hope this helped!

8 0
3 years ago
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Please help me!! I’ll give brainliest
vlada-n [284]

Answer:

volume = 1134.6 cm³

Step-by-step explanation:

volume = 8.2 x 13.7 x 10.1 = 1134.6 cm³

3 0
3 years ago
Rectangle ABCD was dilated to create rectangle A'B'C'D.
77julia77 [94]

The first thing we must do for this case is to calculate the scale factor.

For this, we make the relationship between two parallel sides.

We have then:

k =\frac{B'C'}{BC}

Substituting values we have:

k = \frac{9.5}{3.8}\\k = 2.5

We are now looking for the value of AB

We have then:

AB = \frac{A'B'}{k}

Substituting values:

AB = \frac{15}{2.5}\\AB = 6

Answer:

The scale factor is:

k = 2.5

The value of AB is:

AB = 6

8 0
3 years ago
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Answer to this please ??
mr_godi [17]

Answer:

31°

Step-by-step explanation:

The upper and lower triangles are similar, because their bases are parallel.

This implies that their correspondent angles have the same measure: the correspondent angle of x is the 31° angle.

7 0
3 years ago
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