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Semmy [17]
3 years ago
15

If 49, out of 175 people like cookies, what is the probability of 1200 people who will like cookies

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
5 0

I'm not really sure, but I believe the probability of 1,200 people liking cookies would be 336 people.

In order to solve this you would have to divide 1200 by 175 and take your answer and multiply that by 49.

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The following data points represent the volume
svetoff [14.1K]

Answer:

The missing volume of gas is 6 liters

Step-by-step explanation:

The following data points represent the volume  of gas in each race car driver's tank (in liters):

4,5, 13, ?

Let the missing value be x

Data : 4,5,13,x

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}

7 = \frac{4+5+13+x}{4}

7 \times 4=4+5+13+x

28=22+x

28-22=x

6=x

Hence The missing volume of gas is 6 liters

3 0
3 years ago
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If correct ill give brainly
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Answer:

Hello! answer: x = 16

Step-by-step explanation:

16 × 16 = 256

12 × 12 = 144

256 + 144 = 400

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Crystal is having a painting party with her friends. Each friend will need two canvases. The equation to find the total number o
Troyanec [42]
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3 years ago
Which of the following lists is ordered from least to greatest?
STALIN [3.7K]

Answer: the one that have -5,0,0.8.1.

Step-by-step explanation:

4 0
3 years ago
Help with 30 please. thanks.​
Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

\displaystyle  y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}

And we want to show that:

\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}

Instead of differentiating directly, we can first square both sides:

\displaystyle y^2 = 3e^{2x} -4x + 1

We can find the first derivative through implicit differentiation:

\displaystyle 2y \frac{dy}{dx}  = 6e^{2x} -4

Hence:

\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}

And we can find the second derivative by using the quotient rule:

\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}

Substitute:

\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}

Combine fractions:

\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}

Simplify:

6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}

Q.E.D.

6 0
2 years ago
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