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SpyIntel [72]
3 years ago
8

Find X(midsegment of a triangle) picture attached

Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

f

Step-by-step explanation:

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Trey evaluated 12/15 + 1/10 and got the answer of 13/25. which statement is true about this answer?
Ganezh [65]

Answer:

Option C. His answer is not correct, because the same can not be less than either attend

Step-by-step explanation:

we have

\frac{12}{15}+\frac{1}{10} =\frac{13}{25}

we know that

\frac{12}{15}=0.8

\frac{1}{10}=0.10

\frac{13}{25}=0.52

substitute

0.80+0.10=0.52 ----> is not true

therefore

His answer is not correct, because the same can not be less than either attend

6 0
3 years ago
For the quadrilateral ABCD, E and F are midpoints of sides AD and BC respectively. AB = 15, BC = 29, CD = 34, AD = 11, and
uranmaximum [27]

Answer:

31

Step-by-step explanation:

31

7 0
3 years ago
Plot the intercepts to graph the equation
natulia [17]
Jsjdhdjsjensbejejdndnsksbdjendkebfkendntjd

8 0
3 years ago
genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. Construct a ​%
Andreas93 [3]

Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The  95%  confidence interval is  0.2392  <  p < 0.3108

No, the confidence interval includes​ 0.25, so the true percentage could easily equal​ 25%

Step-by-step explanation:

From the question we are told that

  The total sample size is  n  =  432 + 164 =596

   The  number of  offspring that is yellow peas is y =  432

   The  number of  offspring that is green peas   is g =  164

   

The sample proportion for offspring that are yellow peas is mathematically evaluated as

        \r p  =  \frac{ 164 }{596}

        \r p  =  0.275

Given the the  confidence level is  95% then the level of significance is mathematically represented as

       \alpha  =  (100 - 95)\%

      \alpha =  5\%  =  0.0 5

The  critical value of  \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} } = 1.96

Generally the margin of error is mathematically evaluated as

        E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }

=>      E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }

=>      E =  0.0358

The  95%  confidence interval is mathematically represented as

      \r p - E  <  p < \r p + E

=>   0.275 -  0.0358  <  p < 0.275 +  0.0358

=>   0.2392  <  p < 0.3108

6 0
3 years ago
Write 64 in expanded from
lozanna [386]
Um im guessing 60 +4 or sixty four
3 0
4 years ago
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