X/3=2
x=6
x/5=3
x=15
x/7=2
x=14
Each time, you multiply both sides by the denominator.
Hope this helps :)
We have equation:
t=20x+31
x is number of years after 1997.
To calculate number of laptops in 2005:
x=2005-1997
x=8
t=20*8+31
t=160+31
t=191
In year 2005 school had 191 laptops.
Complete the Square:
Plug your numbers in this function
You get this
That equals 
Answer:
Any number from 1-5
Step-by-step explanation:
Less than 6!
Answer:
37.59 nautical miles
Explanation:
Distance = Speed x Time
The speed of the first ship = 12 knots
Thus, the distance covered after 1.5 hours

The speed of the second ship = 22 knots
Thus, the distance covered after 1.5 hours

The diagram representing the ship's path is drawn and attached below:
The angle at port = 90 degrees.
The triangle is a right triangle.
Using Pythagorean Theorem:
![\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20c%5E2%3D18%5E2%2B33%5E2%20%5C%5C%20c%5E2%3D324%2B1089%20%5C%5C%20c%5E2%3D1413%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B1413%7D%20%5C%5C%20c%3D37.59%5Ctext%7B%20miles%7D%20%5Cend%7Bgathered%7D)
The two ships are 37.59 nautical miles apart after 1.5 hours.