(2x^1/6 over 3y^4)^-3 It's past 2am and I would like to sleep a little bit.
1 answer:
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Answer:
The standard deviation would have to be 0.05.
Step-by-step explanation:
We can solve this problem using the 68-95-99.7 rule for normal distributions:
The rule states that:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviations of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
What would the value of σ have to be to ensure that 95% of all readings are within 0.1° of μ?
This means that 2 standard deviations would need to be within 0.1 of the mean. So
The standard deviation would have to be 0.05.