Answer:
Area of pool part = Area of large rectangle - Area of the pool
Area of pool area = Area of the pool = 40 × 60 = 2400 ft²
2400 = Area of large rectangle - 2400
Area of massive rectangle = 2400 + 2400
Area of big rectangle = 4800
Length × width = 4800
From the diagram, we need the length to be [x + x] more than the period of the pool, wherein x is the distance from the pool facet to the patio area.
We also want the width of the huge rectangle to be [[x + x] more than the width of the pool.
Length = 60 + 2x
Width = 40 + 2x
Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
zero = 4[x² + 50x - 600]
0 = x² + 50x - 600
zero = [x - 60] [x + 10]
x - 60 = 0 OR x + 10 = zero
x = 60 OR x = -10
We can only use the positive price of x for the reason that context is duration.
x = 60