F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
Graph 4
Step-by-step explanation:
Graph 4 does not belong. This is as a result of the fact that it Graph 4 has a negative slope(descends) while all other graphs have a positive slope(ascends).
Another way to view it is that the values in Graphs 1, 2 and 3 are directly related while the values in Graph 4 are inversely related.
The answer is 325, 20 + 205 + 100 = 325
Answer:
100°
Step-by-step explanation:
A triangle is a polygon shape with three sides. Triangles are of different types such as obtuse, scalene, equilateral, isosceles etc.
In triangle ABC:
70° + 50° + ∠C = 180° (sum of angles in a triangle)
120 + ∠C = 180
∠C = 180 - 120
∠C = 60°
Since ∠C is bisected into ∠ACD and ∠BCD, hence:
∠ACD = ∠BCD = ∠C / 2
∠ACD = ∠BCD = 60 / 2
∠ACD = ∠BCD = 30°
In triangle ACD:
∠A + ∠ACD + ∠ADC = 180° (sum of angles in a triangle)
50 + 30 + ∠ADC = 180
∠ADC + 80 = 180
∠ADC = 100°
