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astraxan [27]
3 years ago
7

I have 30 ones, 82 thousands, 4 hundred thousands, 60 tens, and 100 hundreds. What number am I?

Mathematics
1 answer:
stich3 [128]3 years ago
7 0
This problem tackles the place values of numbers. From the rightmost end of the number to the leftmost side, these place values are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, one hundred millions, and so on and so forth. My idea for the solution of this problem is to add up all like multiples. In this problem, there are 5 multiples expressed in ones, thousands, hundred thousands, tens and hundreds. Hence, you will add up 5 like terms. The solution is as follows

30(1) + 82(1,000) + 4(100,000) + 60(10) + 100(100)

The total answer is 492,630. Therefore, the number's identity is 492,630.
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Step-by-step explanation:

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Answer:

Probability that a  house has a hot tub given that it has a pool is 55%.

Step-by-step explanation:

We are given that in New York State, 38% of the houses have a pool and 21% of the houses have both a pool and a hot tub.

Let the probability that houses have a pool = P(A) = 0.38

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Now, the conditional probability that a  house has a hot tub given that it has a pool is given by =  P(B / A)

<u>As we know that</u>;   P(B / A)  =  \frac{P(A \bigcap B)}{P(A) }

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