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astraxan [27]
3 years ago
7

I have 30 ones, 82 thousands, 4 hundred thousands, 60 tens, and 100 hundreds. What number am I?

Mathematics
1 answer:
stich3 [128]3 years ago
7 0
This problem tackles the place values of numbers. From the rightmost end of the number to the leftmost side, these place values are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, one hundred millions, and so on and so forth. My idea for the solution of this problem is to add up all like multiples. In this problem, there are 5 multiples expressed in ones, thousands, hundred thousands, tens and hundreds. Hence, you will add up 5 like terms. The solution is as follows

30(1) + 82(1,000) + 4(100,000) + 60(10) + 100(100)

The total answer is 492,630. Therefore, the number's identity is 492,630.
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Brian usually brushes his teeth in the morning, but 10% of the time he forgets. What is the probability that he will forget to b
Katena32 [7]

Using it's concept, it is found that there is a 0.001 = 0.1% probability that he will forget to brush his teeth three days in a row.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, for each day, there is a 0.1 probability that he forgers to brush his teeth, and days are independent, hence for 3 consecutive days the probability is given by:

p = (0.1)³ = 0.001.

More can be learned about probabilities at brainly.com/question/14398287

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5 0
2 years ago
True or False
Nady [450]

Answer:

an expression, the exponent indicates how

any times the base is used as a factor. false.

Step-by-step explanation:

beacuse i guess iam smart

3 0
3 years ago
Do you agree or disagree
lakkis [162]
Disagree she needs 7 cups of bananas because 1.75×4=7  
3 0
3 years ago
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wolverine [178]
A proper fraction is a fraction less than one, with the numerator less than the denominator so 1/2 is your answer
4 0
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Oksana_A [137]
If I understand your question well, I suppose you mean \frac{4}{ x^{2} -35} -  \frac{1}{x+5}
\frac{4}{ x^{2} -35} - \frac{1}{x+5} =  \frac{4}{(x+5)(x-7)}- \frac{1}{x+5} \\ = \frac{1}{x+5}( \frac{4}{x-7}-1) \\ = \frac{1}{x+5}( \frac{4}{x-7}- \frac{x-7}{x-7}) \\ = \frac{1}{x+5}( \frac{4-x+7}{x-7}) \\ = \frac{1}{x+5}( \frac{11-x}{x-7}) \\ = \frac{11-x}{ x^{2} -35}
6 0
3 years ago
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